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One Response to “How many possible combinations are there in a 6/42 lotto?”
By shinta80 on Oct 14, 2008 | Reply
if you think that every combination would be possible
and 6 digit number is required
then the way should be like this
first digit could be 1 of the 42 possible number
second digit could be 1 of the 42 possible number
third…
.
Sixth Digit ……
then the result will be 42*42*42*42*42*42= 5 489 031 744
if you could eliminate some probabilities or choices such as
111111, 123456 etc.. the combinations will be less.